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Ex � 1
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Example 1Change 123 x 456 as 12 x 457
Cambiar 123 x 456 como 12 x 457
Mude 123 x 456 como 12 x 457
Änderen Sie 123 x 456 wie 12 x 457
Changez 123 x 456 pour 12 x 457
Cambiare 123 x 456 come 12 x 457
Verander 123 x 456 naar 12 x 457
Ret 123 x 456 til 12 x 457
123 x 456 12 x 457
Zamie 123 x 456 na 12 x 457
123 x 456 12 x 457
Ubahlah 123 x 456 menjadi 12 x 457
123×45612×457
123 [ x ] 45 [ ]1 2 3 4 5
5535.DD
[ ] [ ] [ ] [ DEL ]1 2 4 5
DD
[ 2nd ] [ ]1 2 3 4 5
DD
[ ] [ ] 7 [ ]1 2 3 4 7 5
58425.DD
Example 2After executing 1+ 2, 3 + 4, 5 + 6, use replay function to recall
Ex � 2
Después de ejecutar 1 + 2, 3 + 4, 5 + 6, use la función replay pararevocar
Depois de executar 1 + 2, 3 + 4, 5 + 6, use função replay pararechamar
Nach der Eingabe von 1 + 2, 3 + 4, 5 + 6, benutzen Sie dieReplay-Funktion zum Wiederholen
Après avoir exécuté 1 + 2, 3 + 4, 5 + 6, utilisez la fonction derépétition pour rappeler
Dopo avere eseguito 1 + 2, 3 + 4, 5 + 6, usa funzione ripetuta(replay) perrichiamare
Na het uitvoeren van 1 + 2, 3 + 4, 5 + 6, gebruikt u deherhaalfunctie om op te vragen
Når du har udført 1+ 2, 3 + 4, 5 + 6, kan du brugegentagelsesfunktionen til at hente
1 + 2, 3 + 4, 5 + 6,
Po wykonaniu 1 + 2, 3 + 4, 5 + 6, zastosuj funkcj replay abywywo a z pami ci
1 + 2, 3 + 4, 5 + 6 , 3
Setelah mengeksekusi 1 + 2, 3 + 4, 5 + 6, gunakan fungsi replayuntuk memanggil kembali
1+23+45+6
1 [ + ] 2 [ ] 3 [ + ] 4 [ ]5 [ + ] 6 [ ] 5 + 6
11.DD
[ ]5 + 6
DD
[ ]3 + 4
DD
[ ]1 + 2
DD
Example 314 ) 0 x 2.3 mistakenly input instead of 14 )10 x 2.3
14 ) 0 x 2.3 equivocadamente digitado en lugar de 14 )10 x 2.3
Ex � 3
14 ) 0 x 2.3 eradamente digitada em vez de 14 )10 x 2.3
14 ) 0 x 2.3 irrtümlicherweise an Stelle von 14 )10 x 2.3eingegeben
Entrée erronée de14 ) 0 x 2.3 au lieu de 14 )10 x 2.3
14 ) 0 x 2.3 sbagliatamente entrato invece di 14 )10 x 2.3
In plaats van 14 ÷ 10 x 2.3, voerde u 14 ÷ 0 x 2.3 in
14 ÷ 0 x 2.3 indtastet ved en fejl i stedet for 14÷10 x 2.3
14 ÷ 0 x 2.3 14 ÷ 10 x 2.3
14 ) 0 x 2.3 omy kowo wprowadzono zamiast 14 )10 x 2.3
14 ) 10 x 2.3 14 ) 0 x 2.3
14 ÷ 0 x 2.3 telah keliru dimasukkan, padahal seharusnya 14 ÷ 10x 2.3
14÷0×2.314÷10×2.3
14 [ ) ] 0 [ x ] 2.3 [ ]D I V I D E B Y 0
DD
( 5 Seconds )1 4 / 0 2 . 3
DD
[ ] 1 [ ]1 4 / 1 0 2 . 3
3.22DD
Example 4[ ( 3 x 5 ) + ( 56 ) 7 ) � ( 74 � 8 x 7 ) ] = 5
3 [ x ] 5 [ M+ ]3 5
15.DD
M
56 [ ) ] 7 [ M+ ]5 6 / 7
8.DD
M
[ MRC ] [ ]M
23.DD
M
Ex � 4
74 [ � ] 8 [ x ] 7 [ 2nd ] [ M � ] 74 � 8 * 7
18.DD
M
[ MRC ] [ ]M
5.DD
M
[ MRC ] [ MRC ] [ CL/ESC ]
DD
Example 5Put the value 30 into variable APonga el valor 30 en la variable APonha o valor 30 na variável ASetzen Sie den Wert 30 für die Variable APlacez la valeur 30 dans la variable AMetti il valore 30 nella variabile ASla de waarde 30 in de variabele A opMasukkan nilai 30 ke variabel A
30 AWarto 30 zapisz do rejestru pami ci A
A 30Masukkan nilai 30 ke variabel A
30A
[ 2nd ] [ CL-VAR ] 30 [ SAVE ] [ A ][ ] 3 0 A
DD
30.
Multiple 5 to variable A, then put the result into variable BMultiplicar 5 a la variable A, entonces ponga el resultado envariable BMultiplique 5 para variável A, depois ponha o resultado navariável BMultiplizieren Sie 5 mit der Variablen A und setzen Siedieses Ergebnis für die Variablen BMultipliez 5 par la variable A, puis placez le résultat dans lavariable BMoltiplicare 5 a variabile A, poi metti il risultato nellavariabile BVermenigvuldig 5 met de variabele A, en sla het resultaatvervolgens in de variabele B opGang 5 med variabel A, og placer resultatet i variabel B
5 A,B
Ex � 5
Z Zawarto rejestru pami ci A pomnó rpzez 5, a wynikzapisz do rejestru pami ci
A 5 BVariabel A dikalikan dengan 5, kemudian masukkanhasilnya ke variabel B
5 [ x ] [ 2nd ] [ VRCL ]3 0 A
DD
30.
[ ] [ ]5 3 0
150.DD
[ SAVE ] [ B ] [ ]A n s B
DD
150.
Add 3 to variable BAgregue 3 a variable BSome 3 a variável BFügen Sie 3 der Variablen B zuPour clarifier le contenu de toutes les variablesAddizionare 3 a variabile BVoeg 3 aan de inhoud van variabele B toeLæg 3 til variabel B
3 BDo rejestru pami ci B dodaj 3
B 3Tambahkan 3 ke variabel B
3B
[ ALPHA ] [ B ]B
DD
[ + ] 3 [ ]B + 3
153.DD
To clear the contents of all variablesPara cancelar los contenidos de todas las variablesPara apagar os conteúdos de todas as variável BLöschen Sie den Inhalt aller VariablenPour clarifier le contenu de toutes les variablesPer sgombrare i contenuti di tutte le variabileWis de inhoud van alle variabelen
Ex � 6
For at rydde indholdet i alle variabler,
Aby wyzerowa wszystkie rejestry pami ci
Menghapus isi dari seluruh variable
[ 2nd ] [ CL-VAR ] [ 2nd ] [ VRCL ]A B C D E F
DD
G H I
J K L
Example 6Set PROG 1 = cos (3A) + sin (5B), where A = 0, B = 0Fijar PROG 1 = cos (3A) + sin (5B), donde A = 0, B = 0Fixe PROG 1 = cos (3A) + sin (5B), onde A = 0, B = 0Einstellung PROG 1 = cos (3A) + sin (5B), wobie A = 0, B = 0Set PROG 1 = cos (3A) + sin (5B), où A = 0, B = 0Impostare PROG 1 = cos (3A) sin (5B), dove A = 0, B = 0Instellen van PROG 1 = cos (3A) + sin (5B), waarbij A = 0 enB = 0Sæt PROG 1 = cos (3A) + sin (5B), hvor A = 0, B = 0
PROG 1 = cos (3A) + sin (5B), A = 0, B = 0Zapisa program PROG 1 = cos (3A) + sin (5B), gdzie A = 0,B = 0
PROG 1 = cos (3A) + sin (5B), A = 0, B = 0Tetapkan PROG 1 = cos (3A) + sin (5B), di mana A = 0, B = 0
[ COS ] 3 [ ALPHA ] [ A ] [ ] [ + ][ SIN ] 5 [ ALPHA ] [ B ] [ ] 3 A ) + s i n ( 5 B )
DD
[ SAVE ] [ PROG ] 1( 5 B ) PROG 1
DD
[ ]c o s ( 3 A ) + s i n
1.DD
Set A = 20,B = 18, get PROG 1 = cos (3A) + sin (5B) = 1.5Establecer A = 20,B = 18, obtener PROG 1 = cos (3A) + sin(5B) = 1.5Estabelecer A = 20,B = 18, obtenha PROG 1 = cos (3A) +sin (5B) = 1.5Setzen Sie A = 20,B = 18, Sie bekommen PROG 1 = cos(3A) + sin (5B) = 1.5Définissez A = 20,B = 18, et vous obtenez PROG 1 = cos
Ex � 7
(3A) + sin (5B) = 1.5Regola A = 20,B = 18, ottieni PROG 1 = cos (3A) + sin (5B)= 1.5Geef A = 20 en B = 18 op, en verkrijg de oplossing PROG 1= cos (3A) + sin (5B) = 1.5Sæt A = 20,B = 18, get PROG 1 = cos (3A) + sin (5B) = 1.5
A = 20,B = 18, PROG 1 = cos (3A) +sin (5B) = 1.5Nadaj warto ci A = 20,B = 18, jako wynik otrzymasz PROG 1= cos (3A) + sin (5B) = 1.5
A = 20,B = 18, PROG 1 = cos (3A) + sin (5B) = 1.5Tetapkan A = 20,B = 18, untuk mendapatkan PROG 1 = cos(3A) + sin (5B) = 1.5
[ PROG ] 1 [ ] [ ][ CL/ESC ] 20 A = 20
DD
[ ] [ CL/ESC ] 18B = 18
DD
[ ]c o s ( 3 A ) + s i n
1.5DD
Example 7To expand the number of memories by 2 to bring the total to28Para ampliar la cantidad de memorias en 2 y disponer de untotal de 28Para ampliar o número de memórias por 2 para obter o totalde 28Um die Speicherzahl durch 2 zu erweitern, um die Gesamtzahlauf 28 zu bringenPour augmenter le nombre de mémoires par 2 et amener letotal à 28Per espandere il numero di memorie di 2 per portare il totalea 28Het aantal geheugens met 2 uitbreiden zodanig dat hettotale aantal op 28 komt te staanFor at udvide antallet af hukommelser med 2, så detsamlede antal kommer op på 28
2,28.
Powi kszy liczb rejestrów pami ci o 2, tzn. do 28 ogó em2 28
Ex � 8
Memperluas banyaknya memori dua kali lipat sehinggatotalnya adalah 28
228
[ MATH ] [ MATH ] [ MATH ][ MATH ] [ ] 0 n P r 1 n C r
DD
2 D e f m
[ ] 2D e f m 2
DD
[ ]M � 2 8 S � 3 7 6
DD
Put the value 66 into variable A [ 27 ]Ponga el valor 66 en la variable A [ 27 ]Ponha o valor 66 dentro da variável A [ 27 ]Setzen Sie den Wert 66 in die Variable A [ 27 ]Inscrivez la valeur 66 dans la variable A [ 27 ]Mettere il valore 66 nella variabile A [ 27 ]Sla de waarde 66 in de variabele A [ 27 ] opPlacer værdien 66 i variabel A [ 27 ]
66 A [ 27 ]Zapisa warto 66 do rejestru A [ 27 ]
A [ 27 ] 66Masukkan nilai 66 ke variabel A [ 27 ]
66A]27[
66 [ SAVE ] [ A ] [ ALPHA ] [ [ ] ]27 [ ]
6 6 A [ 2 7 ]
DD
66.
Recall variable A [ 27 ]Recupere la variable A [ 27 ]Rechame variável A [ 27 ]Rufen Sie Variable A [ 27 ]Rappelez la variable A [ 27 ] wieder aufRechiamare la variabile A [ 27 ]Opvragen van variabele A [ 27 ]Hent variabel A [ 27 ]
, A[ 27 ]Wywo a zmienn A [ 27 ]
A [ 27 ]Panggilah variabel A [ 27 ]
Ex � 9
[ ALPHA ] [ A ] [ ALPHA ] [ [ ] ] 27[ ]
A [ 2 7 ]
DD
66.
To return memory variable to the standard configurationPara volver la variable de memoria a la configuraciónestánderPara retornar a variável de memória à configuração padrãoUm die Speichervariable zur Standkonfiguration zurückzubringenPour faire revenir la variable de mémoire à la configurationstandardPer riportare la variabile di memoria alla configurazionestandardHerstelt de geheugenvariabelen naar de standaardinstellingFor at bringe hukommelsesvariablen tilbage tilstandardkonfigurationen
Powróci do standardowej konfiguracji pami ci
Mengembalikan variabel memori ke konfigurasi standar
[ MATH ] [ MATH ] [ MATH ][ MATH ] [ ] 0 n P r 1 n C r
DD
2 D e f m
[ ] 0 [ ]M � 2 6 S � 4 0 0
DD
Example 87 + 10 x 8 ) 2 = 47
7 [ + ] 10 [ x ] 8 [ ) ] 2 [ ]7 + 10 8 / 2
47.DD
Example 9� 3.5 + 8 ) 4 = 0.5
[ ( � ) ] 3.5 [ + ] 8 [ ) ] 4 [ ]� 3 . 5 + 8 / 4
� 1.5DD
Example 10
Ex � 10
12369 x 7532 x 74103 = 6903680613000
12369 [ x ] 7532 [ x ] 74103[ ] 1 2 3 6 9 7 5 3 2
6.903680613x10
12
DD
Example 116 ) 7 = 0.857142857
6 [ ) ] 7 [ ]6 / 7
0.857142857DD
[ 2nd ] [ FIX ] [ ] [ ] [ ]F 0 1 2 3 4 5 6 7 8 9
DD
[ ]6 / 7
0.86DD FIX
[ 2nd ] [ FIX ] 46 / 7
0.8571DD FIX
[ 2nd ] [ FIX ] [ � ] 6 / 7
0.857142857DD
Example 121 ) 6000 = 0.0001666...
1 [ ) ] 6000 [ ]1 / 6 0 0 0
0.000166667DD
[ 2nd ] [ SCI / ENG ] [ ]F L O S C I E N G
DD
Ex � 11
[ ]1 / 6 0 0 0
1.666666667DD SCI
x10� 04
[ 2nd ] [ SCI / ENG ] [ ]F L O S C I E N G
DD SCI
[ ]1 / 6 0 0 0
166.6666667DD ENG
x10� 06
[ 2nd ] [ SCI / ENG ] [ ]F L O S C I E N G
DD ENG
[ ]1 / 6 0 0 0
0.000166667DD
Example 130.0015 = 1.5 x 10
� 3
1.5 [ EXP ] [ (�) ] 3 [ ]1 .5 E
� 3
0.0015DD
Example 1420 G byte + 0.15 K byte = 2.000000015 x 10
10byte
20 [ 2nd ] [ ENG SYM ] [ ] [ ]0 K 1 M 2 G
DD
3 T 4 P
5 E
[ ] [ + ] 0.15 [ 2nd ] [ ENGSYM ] 0 K 1 M 2 G
DD
3 T 4 P
5 E
Ex � 12
[ ] [ ]2 0 G + 0 .1 5 K
2.000000015DD
x1010
Example 15 ( 5 � 2 x 1.5 ) x 3 = 6
[ ( ) ] 5 [ � ] 2 [ x ] 1.5 [ ] [ x ] 3[ ] ( 5 � 2 1 . 5 ) 3
6.DD
Example 162 x { 7 + 6 x ( 5 + 4 ) } = 122
2 [ x ] [ ( ) ] 7 [ + ] 6 [ x ] [ ( ) ] 5 [ + ]4 [ ] 2 ( 7 + 6 ( 5 + 4
122.DD
Example 17120 x 30 % = 36
120 [ x ] 30 [ 2nd ] [ % ] [ ]1 2 0 3 0 %
36.DD
88 ) 55% = 160
88 [ ) ] 55 [ 2nd ] [ % ] [ ]8 8 / 5 5 %
160.DD
Example 183 x 3 x 3 x 3 = 81
3 [ x ] 3 [ ]3 3
9.DD
[ x ] 3 [ ]A n s 3
27.DD
Ex � 13
[ ]A n s 3
81.DD
To calculate ) 6 after 3 x 4 = 12Para calcular ) 6 después de 3 x 4 = 12Para calcular ) 6 depois de 3 x 4 = 12Berechnen Sie ) 6 nach 3 x 4 = 12Pour calculer ) 6 aprés 3 x 4 = 12Per calcolare ) 6 dopo 3 x 4 = 12Voer ÷ 6 uit, na de bewerking 3 x 4 = 12For at beregne ÷ 6 efter 3 x 4 = 12
÷ 6 3 x 4 = 12Aby obliczy ÷ 6 po 3 x 4 = 12
3 x 4 = 12 ) 6Menghitung ÷ 6 setelah 3 x 4 = 12
6÷3×4=12
3 [ x ] 4 [ ]3 4
12.DD
[ ) ] 6 [ ]A n s / 6
2.DD
Example 19123 + 456 = 579 789 � 579 = 210
123 [ + ] 456 [ ]1 2 3 + 4 5 6
579.DD
789 [ � ] [ 2nd ] [ ANS ] [ ]7 8 9 � A n s
210.DD
Example 20ln7 + log100 =3.945910149
[ LN ] 7 [ ] [ + ] [ LOG ] 100[ ] l n ( 7 ) + l o g ( 1
DD
3.945910149
Ex � 14
102
= 100
[ 2nd ] [ 10 x ] 2 [ ]1 0 ( 2 )
DD
100.
e� 5
= 0.006737947
[ 2nd ] [ e x ] [ ( � ) ] 5 [ ]e ( � 5 )
DD
0.006737947
Example 21
7 [ A b/c ] 2 [ A b/c ] 3 [ + ] 14 [ A b/c ]5 [ A b/c ] 7 [ ] 7 2 3 + 1 4 5
DD
22 U 8 21
Example 22
4 [ A b/c ] 2 [ A b/c ] 4 [ ]4 2 4
DD
4 U 1 2
[ 2nd ] [ Ab/cd/e ] [ ]
Ans Ab/c d/e
DD
9 2
[ 2nd ] [ Ab/cd/e ] [ ]
Ans Ab/c d/e
DD
4 U 1 2
Example 23
4 [ A b/c ] 1 [ A b/c ] 2 [ 2nd ][ F D ] [ ] 4 1 2 F D
DD
4.5
Ex � 15
Example 24
8 [ A b/c ] 4 [ A b/c ] 5 [ + ] 3.75[ ] 8 4 5 + 3.75
DD
12.55
Example 25
2 rad. = 360 deg.
[ DRG ]D E G R A D G R D
DD
[ ] 2 [ 2nd ] [ ] [ 2nd ]
[ DMS ] [ ] [ ] [ ]º r g
DD
DMS
[ ] [ ]2 r
DD
360.
Example 261.5 = 1
O30
I0
II( DMS )
1.5 [ 2nd ] [ DMS ] [ ]º r g
DD
DMS
[ ] [ ]1.5 D M S
DD
1 30 I 0 II
Example 272
O45
I10.5
II= 2.752916667
2 [ 2nd ] [ DMS ]º r g
DD
DMS
Ex � 16
[ ] 45 [ 2nd ] [ DMS ] [ ]º r g
DD
DMS
[ ] 10.5 [ 2nd ] [ DMS ] [ ][ ] º r g
DD
DMS
[ ] [ ]2 º 4 5 1 0. 5
DD
2.752916667
Example 28sin30 Deg. = 0.5
[ DRG ]D E G R A D G R D
DD
[ ] [ SIN ] 30 [ ]s i n ( 3 0 )
DD
0.5
sin30 Rad. = � 0.988031624
[ DRG ] [ ]D E G R A D G R D
DD
[ ] [ SIN ] 30 [ ]s i n ( 3 0 )
RR
� 0.988031624
sin�1
0.5 = 33.33333333 Grad.
[ DRG ] [ ]D E G R A D G R D
RR
[ ] [ 2nd ] [ SIN �1 ] 0.5[ ] s i n � 1 ( 0 . 5 )
GG
33.33333333
Ex � 17
Example 29cosh1.5+2 = 4.352409615
[ 2nd ] [ HYP ] [ COS ] 1.5 [ ][ + ] 2 [ ] c o s h ( 1 . 5 ) + 2
DD
4.352409615
sinh�1
7 = 2.644120761
[ 2nd ] [ HYP ] [ 2nd ] [ SIN �1] 7[ ] s i n h � 1 ( 7 )
DD
2. 644120761
Example 30
If x = 5, y = 30, what are r, ? Ans : r = 30.41381265, =80.53767779 °Six x = 5 , y = 30, lo que es r, ? Resp : r = 30.41381265, =80.53767779 °Sex x = 5 , y = 30, o que é r, ? Resp : r = 30.41381265, =80.53767779 °Falls x = 5, y = 30, was sind r, ? Antw : r = 30.41381265, =80.53767779 °Six x = 5 , y = 30, cobien vaut r, ? Rép : r = 30.41381265, =80.53767779 °Se x = 5 , y = 30, Che sono r, ? Risp : r = 30.41381265, =80.53767779 °Indien x = 5 en y = 30, hoeveel is dan r en ? Antwoord : r =
30.41381265 en = 80.53767779
Hvis x = 5 , y = 30, hvad er så r, ? Svar : r = 30.41381265, =80.53767779 °
x = 5, y = 30, r, ? : r = 30.41381265,=80.53767779 °Je�li x = 5 , y = 30, to jakie s warto ci r, ? Odp : r =
30.41381265, = 80.53767779 °
x = 5 , y = 30, r : r = 30.41381265, = 80.53767779 °
Jika x = 5 , y = 30, berapakah r, ? Jawab : r = 30.41381265, =80.53767779 °
[ 2nd ] [ R P ]R P r R P
DD
P R x
P R y
Ex � 18
[ ] 5 [ ALPHA ] [ ] 30[ ]
R P r ( 5 , 30 )
DD
30.41381265
[ 2nd ] [ R P ] [ ]R P r R P
DD
P R x
P R y
[ ] 5 [ ALPHA ] [ ] 30[ ]
R P ( 5 , 30 )
DD
80.53767779
If r = 25, = 56°, what are x , y ? Ans : x = 13.97982259, y =20.72593931Six r = 25, = 56°, lo que es x , y? Resp : x = 13.97982259, y =20.72593931Sex r = 25, = 56°, o que é x , y? Resp : x = 13.97982259, y =20.72593931Falls r = 25, = 56°, was sind x , y? Antw : x = 13.97982259, y =20.72593931Six r = 25, = 56°, cobien vaut x , y? Rép : x = 13.97982259, y =20.72593931Se r = 25, = 56°, Che sono x , y ? Risp : x = 13.97982259, y =20.72593931Indien r = 25 en = 56? Hoeveel is dan x en y ? Antwoord : x =13.97982259 en y = 20.72593931Hvis r = 25, = 56, hvad er så x , y ? Svar : x = 13.97982259, y =20.72593931
r = 25, = 56°, x , y? : x = 13.97982259, y= 20.72593931Je li r = 25, = 56°, to jakie s warto ci x , y? Odp : x =13.97982259, y = 20.72593931
r = 25, = 56°, x y : x = 13.97982259, y =20.72593931Jika r = 25, = 56? berapakah x , y ? Jawab : x = 13.97982259, y= 20.72593931
[ 2nd ] [ R P ] [ ]R P r R P
DD
P R x
P R y
Ex � 19
[ ] 25 [ ALPHA ] [ ] 56[ ]
P R x ( 2 5 , 5 6 )
DD
13.97982259
[ 2nd ] [ R P ] [ ] [ ]R P r R P
DD
P R x
P R y
[ ] 25 [ ALPHA ] [ ] 56[ ]
P R y ( 2 5 , 5 6 )
DD
20.72593931
Example 315 ! = 120
5 [ MATH ]0 ! 1 R A N D
DD
2 R A N D I
3 R N D
[ ] [ ]5 !
DD
120.
Generates a random number between 0 and 1Generar un número aleatorio entre 0 y 1Gera um número randomico entre 0 e 1Erzeugt eine zufälligen Zahl zwischen 0 und 1Produisez un chiffre au hasard entre 0 et 1Genera un numero casuale tra 0 et 1Genereert een willekeurig getal tussen 0 en 1Genererer et tilfældigt tal mellem 0 og 1
0 1Generuje losow liczb ca kowit zawart mi dzy 0 i 1
0 1Menghasilkan sebuah bilangan acak antara 0 dan 1
01
[ MATH ] [ ]0 ! 1 R A N D
DD
2 R A N D I
3 R N D
[ ] [ ]R A N D
DD
0.103988648
Ex � 20
Generates a random integer between 7 and 9Genera un entero aleatorio entre 7 y 9Gera um inteiro randomico entre 7 e 9Erzeugt eine Zufallszahl zwischen 7 und 9Génère un entier au hasard entre 7 et 9Genera un numero intero casuale fra 7 e 9Genereert een willekeurig getal tussen 7 en 9Genererer et tilfældigt heltal mellem 7 og 9
7 � 9 Wygenerowa przypadkw liczb ca kowit z zakresu od 7 do 9
7 9Menghasilkan sebuah bilangan bulat acak antara 7 dan 9
79
[ MATH ] [ ]0 ! 1 R A N D
DD
2 R A N D I
3 R N D
[ ] 7 [ ALPHA ] [ ] 9[ ] R A N D I ( 7 , 9 )
DD
8.
RND ( sin 45 Deg. ) = 0.71 ( FIX = 2 )
[ MATH ] [ ] [ ]0 ! 1 R A N D
DD
2 R A N D I
3 R N D
[ ] [ SIN ] 45 [ 2nd ] [ FIX ][ ] [ ] [ ] F 0 1 2 3 4 5 6 7 8 9
DD
[ ] [ ]R N D ( s i n ( 4 5 )
DD
0.71FIX
MAX ( sin 30 Deg. , sin 90 Deg. ) = MAX ( 0.5, 1 ) = 1
[ MATH ] [ MATH ]0 M A X 1 M I N
DD
2 S U M
3 A V G
[ ] [ SIN ] 30 [ ] [ ALPHA ][ ] [ SIN ] 90 [ ] M A X ( s i n ( 3 0 )
DD
1
MIN ( sin 30 Deg., sin 90 Deg. ) = MIN ( 0.5, 1 ) = 0.5
Ex � 21
[ MATH ] [ MATH ] [ ]0 M A X 1 M I N
DD
2 S U M
3 A V G
[ ] [ SIN ] 30 [ ] [ ALPHA ][ ] [ SIN ] 90 [ ] M I N ( s i n ( 3 0 )
DD
0.5
SUM (13, 15, 23 ) = 51
[ MATH ] [ MATH ] [ ]0 M A X 1 M I N
DD
2 S U M
3 A V G
[ ] 13 [ ALPHA ] [ ] 15[ ALPHA ] [ ] 23 [ ] S U M ( 1 3 , 1 5 , 2
DD
51.
AVG (13, 15, 23 ) = 17
[ MATH ] [ MATH ] [ ] [ ]0 M A X 1 M I N
DD
2 S U M
3 A V G
[ ] 13 [ ALPHA ] [ ] 15[ ALPHA ] [ ] 23 [ ] A V G ( 1 3 , 1 5 , 2
DD
17.
Frac (10 ) 8 ) = Frac ( 1.25 ) = 0.25
[ MATH ] [ MATH ] [ MATH ]0 F r a c 1 I N T
DD
2 S G N
3 A B S
[ ] 10 [ ) ] 8 [ ]F r a c ( 1 0 / 8 )
DD
0.25
INT (10 ) 8 ) = INT ( 1.25 ) = 1
[ MATH ] [ MATH ] [ MATH ] [ ]0 F r a c 1 I N T
DD
2 S G N
3 A B S
Ex � 22
[ ] 10 [ ) ] 8 [ ]I N T ( 1 0 / 8 )
DD
1.
SGN ( log 0.01 ) =SGN ( � 2 ) = � 1
[ MATH ] [ MATH ] [ MATH ] [ ]0 F r a c 1 I N T
DD
2 S G N
3 A B S
[ ] [ LOG ] 0.01 [ ]S G N ( l o g ( 0 . 0
DD
� 1.
ABS ( log 0.01) =ABS ( � 2 ) = 2
[ MATH ] [ MATH ] [ MATH ] [ ][ ] 0 F r a c 1 I N T
DD
2 S G N
3 A B S
[ ] [ LOG ] 0.01 [ ]A B S ( l o g ( 0 . 0
DD
2.
7 ! ) [ ( 7 � 4 ) ! ] = 840
7 [ MATH ] [ MATH ] [ MATH ][ MATH ] 0 n P r 1 n C r
DD
2 D e f m
[ ] 4 [ ]7 n P r 4
DD
840.
7 ! ) [ ( 7 � 4 ) ! x 3 ! ] = 35
7 [ MATH ] [ MATH ] [ MATH ][ MATH ] [ ] 0 n P r 1 n C r
DD
2 D e f m
[ ] 4 [ ]7 n C r 4
DD
35.
Ex � 23
Example 32
1.25 [ 2nd ] [ X � 1 ] [ ]1 . 2 5 � 1
0.8DD
2 [ X 2 ] [ + ] [ ] 4 [ + ] 21 [ ]
[ + ] [ 2nd ] [ 3 ] 27 [ ]2 2 + ( 4 + 21 ) +
12.DD
4 [ 2nd ] [ X ] 81 [ ] 4 x ( 8 1 )
3.DD
74
= 2401
7 [ 2nd ] [ ] 4 [ ]7 4
2401.DD
Example 331yd
2= 9 ft
2= 0.000000836 km
2
1 [ 2nd ] [ CONV ] [ 2nd ] [ CONV ][ ] f t 2 y d 2 m 2
DD
m i I e 2
k m 2
[ ]f t 2 y d 2 m 2
DD
m i I e 2
k m 2 1.
[ ]f t 2 y d 2 m 2
DD
m i I e 2
k m 2 9.
Ex � 24
[ ] [ ]f t 2 y d 2 m 2
DD
m i I e 2
k m 2 0.000000836
Example 343 x G = 2.00177955 x 10
�10
3 [ x ] [ 2nd ] [ CONST ] [ ] [ ]0 c 1 V m 2 N A
DD
3 g 4 m e
5 G 6 m P 6.6725985x10
�11
[ ] [ ]3 G
2.00177955x10
�10
DD
Example 35Use Multistatement function to the two statements : ( E = 15 )Use la función de multiinstrucción en las dos instrucciones:( E =15 )Use função Multi Sentença para as duas sentenças : ( E = 15 )Verwenden Sie die Mehrfachaussagefunktion für die zweiAussagen : ( E = 15 )Utilisez une fonction Instructions multiples pour les deuxinstructions : ( E = 15 )Usare la funzione Multistatement con le due frasi : ( E = 15 )Gebruik de Multistatement functie met de twee uitdrukkingen : ( E= 15 )Brug multisætningsfunktionen på de to sætninger : ( E = 15 )
:(E=15)Wykorzysta funkcj wielozadaniow do dwu instrukcji : ( E = 15 )
2 : ( E = 15 )Gunakan fungsi Multistatement untuk dua pernyataan di bawahini : ( E = 15 )
E x 13 = 195
180 E = 12
15 [ SAVE ] [ E ] [ ]15 E
DD
15.
Ex � 25
[ ALPHA ] [ E ] [ x ] 13 [ ALPHA ][ ] 180 [ ) ] [ APLHA ] [ E ]
E 1 3 1 8 0 / E
DD
195.
[ ]E 1 3 1 8 0 / E
DD
12.
[ ]E 1 3 1 8 0 / E
DD
195.
Example 36Graph Y = e
x
[ Graph ] [ 2nd ] [ e x ]r a p h Y = e ^ (
DD
[ ]
DD
Example 37Range : X min = � 180, X max = 180, X scl = 90, Y min = � 1.25, Y max = 1.25, Y scl = 0.5, Graph Y = sin (2 x)
[ Range ] [ (�) ] 180 X m i n = � 1 8 0
DD
[ ] 180 [ ] 90 [ ] [ (�) ] 1.25 [ ] 1.25 [ ] 0.5 Y s c l = 0 . 5
DD
[ ] [ 2nd ] [ Factor ] 2X f a c t = 2
DD
Ex � 26
[ ] 2Y f a c t = 2
DD
[ ] [ Graph ] [ SIN ] 2[ ALPHA ] [ X ] p h Y = s i n ( 2 X
DD
[ ]
DD
[ G T ]
DD
[ G T ]
DD
Use Zoom function to enlarge and reduce Y = sin (2x)Use la función Zoom al para agrandar y reducir Y = sin (2x)Use função Zoom para ampliar e reduzir Y = sin (2x)Verwenden Sie die Zoomfunktion zur Vergrößerung oderreduzierung von Y = sin (2x)Utilisez la fonction Zoom pour agrandir et réduire Y = sin (2x)Usare la funzione dello zoom per allargare e ridurre Y = sin (2x)Teken de grafiek voor Y = cos (X) op de grafiek voor Y = sin ( x )Brug Zoom-funktionen til at forstørre og reducere Y = sin (2x)
ZoomY = sin (2x)
U y funkcj Zoom aby powi kszy i zmniejszy wykres Y = sin(2x)
Y = sin (2x)Gunakan fungsi Zoom untuk memperbesar atau memperkecil Y =sin (2x)
[ 2nd ] [ Zoom x f ]
DD
Ex � 27
[ 2nd ] [ Zoom x f ]
DD
[ 2nd ] [ Zoom Org ]
DD
[ 2nd ] [ Zoom x 1 / f ]
DD
[ 2nd ] [ Zoom x 1 / f ]
DD
Example 38Overdraw the graph for Y = � X + 2 on the graph for Y = X
3+ 3 X
2 �
6 X � 8 Sobreponga el gráfico para Y = � X + 2 sobre el gráfico Y = X
3+
3X2 � 6 X � 8
Delinee o gráfico para Y = � X + 2 sobre o gráficopara Y = X 3
+3X
2 � 6 X � 8
Überziehen Sie den Graphen für Y = � X + 2 auf dem Graphen für Y = X
3+ 3 X
2 � 6 X � 8
Superposez le graphique pour Y = � X + 2 sur le graphique pour Y = X
3+ 3 X
2 � 6 X � 8
Sovrascrivere il grafico di Y = � X + 2 sul grafico di Y = X 3
+ 3 X2 �
6X � 8 Teken de grafiek voor Y = � X + 2 op de grafiek voor Y = X
3+
3X2 � 6 X � 8
Tegn grafen for Y = � X + 2 over grafen for Y = X 3
+ 3 X2 � 6 X � 8
Y = � X + 2 Y =X
3+ 3 X
2 � 6 X � 8
Na o y wykres funkcji Y = � X + 2 na wykres funkcji Y = X 3
+3X
2 � 6 X � 8
Y = � X + 2 Y = X3
+ 3 X2 � 6 X � 8
Buatlah grafik Y = � X + 2 pada grafik Y = X 3
+ 3 X2 � 6 X � 8
[ Range ] [ (�) ] 8 [ ] 8 [ ] 2[ ] [ (�) ] 15 [ ] 15 [ ] 5 Y s c l = 5
DD
Ex � 28
[ ] [ Graph ] [ ALPHA ] [ X ][ 2nd ] [ x 3 ] [ + ] 3 [ ALPHA ] [ X ][ x 2 ] [ � ] 6 [ ALPHA ] [ X ] [ � ] 8
X 3 + 3 X 2 � 6 X � 8
DD
[ ]
DD
[ Graph ] [ (�) ] [ ALPHA ] [ X ] [ + ] 2 r a p h Y = �X + 2
DD
[ ]
DD
Example 39Overdraw the graph for Y = cos (X) on the graph for Y = sin ( x )Sobreponga el gráfico para Y = cos (X) sobre el gráfico Y = sin( x )Delinee o gráfico para Y = cos (X) sobre o gráficopara Y = sin ( x )Überziehen Sie den Graphen für Y = cos (X) auf dem Graphen fürY = sin ( x )Superposez le graphique pour Y = cos (X) sur le graphique pourY = sin ( x )Sovrascrivere il grafico di Y = cos (X) sul grafico di Y = sin ( x )Teken de grafiek voor Y = cos (X) op de grafiek voor Y = sin ( x )Tegn grafen for Y = cos (X) over grafen for Y = sin ( x )
Y = cos (X) Y =sin ( x )Na o y wykres funkcji Y = cos (X) na wykres funkcji Y = sin ( x )
Y = cos (X) Y = sin ( x )Buatlah grafik Y = cos (X) pada grafik Y = sin ( x )
[ Graph ] [ SIN ] [ ]
DD
[ Graph ] [ COS ] [ ALPHA ] [ X ][ ]
DD
Ex � 29
Example 40Use la función Trace para analizar el gráfico para Y = cos ( x )Use la función Trace para analizar el gráfico para Y = cos ( x )Use função de traço Trace para analisar o gráfico para Y = cos( x )Verwenden Sie die Trace-Funktion, um den Graphen für Y = cos( x )Utilisez la fonction Trace pour analyser le graphique pour Y = cos( x )Usare la funzione Trace per analizzare il grafico per Y = cos ( x )Gebruik de Trace functie om de grafiek voor Y = cos ( x ) teanalyserenBrug Trace-funktionen til at analysere grafen for Y = cos ( x )
Y= cos ( x )U y funkcj trasowania do analizy wykresu funkcji Y = cos ( x )
Y = cos ( x )Gunakan fungsi Trace untuk menganalisis grafik Y = cos ( x )
[ Graph ] [ COS ] [ ]
DD
[ Trace ]
DD
� 338.8235294X =
[ ] [ ] [ ]
DD
X =
� 275.2941176
[ 2nd ] [ X Y ]
DD
Y =
0.092268359
Example 41Draw and scroll the graph for Y = cos ( x )Represente y desplace el gráfico para Y = cos ( x )Desenhe e desloque o gráfico para Y = cos ( x )Zeichnen und scrollen Sie den Graphen für Y = cos ( x )Dessinez et faites défiler le graphique pour Y = cos ( x )Tracciare e far scorrere il grafico di Y = cos ( x )Teken en schuif door de grafiek voor Y = cos ( x )Tegn og rul gennem grafen for Y = cos ( x )
Ex � 30
Y = cos ( x )
Narysowa wykres funkcji Y = cos ( x ) i przesun go na ekranieY = cos ( x )
Buatlah dan gulunglah grafik Y = cos ( x )
[ Graph ] [ COS ] [ ] [ ]
DD
[ ] [ ]
DD
[ ] [ ] [ ] [ ] [ ]
DD
Example 42Use Plot function to locate a point on ( 5 , 5 ), ( 5 , 10 ), ( 15 , 15 ),( 18, 15 ), and then use Line function to connect.Use la función posicionar (PLOT) para posicionar un punto en ( 5 ,5 ), ( 5 , 10 ), ( 15 , 15 ), ( 18, 15 ), y después use la función Linepara conectarlos.Use função tracejante plot para localizar um ponto em ( 5 , 5 ), ( 5 ,10 ), ( 15 , 15 ), ( 18, 15 ), e então use função linha Line paraconectar.Verwenden Sie die Plotfunktion, um einen Punkt auf ( 5 , 5 ), ( 5 ,10 ), ( 15 , 15 ), ( 18, 15 ), zu likalisieren und dann verwenden Siedie Zeilenfunktion zur Verbindung.Utilisez la fonction Plot (coordonnées) pour localiser un point sur( 5 , 5 ), ( 5 , 10 ), ( 15 , 15 ), ( 18, 15 ), puis utilisez la fonctionLigne pour s�y connecter. Usare la funzione Plot per individuare un punto su ( 5 , 5 ), ( 5 ,10 ), ( 15 , 15 ), ( 18, 15 ), ed allora usare funzione Line percollegare.Gebruik de Plot functie om een punt op ( 5 , 5 ), ( 5 , 10 ), ( 15 , 15 )en ( 18, 15 ) te vinden en gebruik vervolgens de Line functie om teverbinden.Brug Plot-funktionen til at finde et punkt på ( 5 , 5 ), ( 5 , 10 ), ( 15 ,15 ), ( 18, 15 ), og brug derefter Line-funktionen til at forbinde.
( 5 , 5 ), ( 5 , 10 ), ( 15 , 15 ), ( 18, 15 ),.
Wyznaczy punkty o wspó rz dnych ( 5 , 5 ), ( 5 , 10 ), ( 15 , 15 ),( 18, 15 ), i po czy je lini aman .
Ex � 31
( 5 , 5 ), ( 5 , 10 ), ( 15 , 15 ), ( 18, 15 )
Gunakan fungsi Plot untuk mementukan kedudukan titik-titik pada( 5 , 5 ), ( 5 , 10 ), ( 15 , 15 ), ( 18, 15 ), dan kemudian gunakanfungsi Line untuk menghubungkan titik-titik itu.
[ Range ] 0 [ ] 35 [ ] 5 [ ] 0[ ] 23 [ ] 5 Y s c l = 5
DD
[ ] [ 2nd ] [ Plot ] 5[ ALPHA ] [ ] 5 P L O T ( 5 , 5
DD
[ ]
X =
5.147058824DD
[ 2nd ] [ X Y ]
Y =
5.227272727DD
[ 2nd ] [ X Y ] [ 2nd ] [ Plot ] 5
[ ALPHA ] [ ] 10 [ ]
DD
X =
5.147058824
[ 2nd ] [ Line ] [ ]
DD
[ 2nd ] [ Plot ] 15 [ ALPHA ] [ ]15 [ ] [ 2nd ] [ Line ][ ]
DD
[ 2nd ] [ Plot ] 18 [ ALPHA ] [ ]15 [ ] [ ] [ ] [ ] [ ][ ] [ ] [ ] [ ] X =
25.73529412DD
Ex � 32
[ 2nd ] [ Line ] [ ]
DD
Example 43Enter data : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 ,FREQ2 = 9, X 3 = 12, FREQ3 = 7, then find out x = 7.5, Sx =3.745585637, Cax = 0 , and Cpx = 0.503655401Entre datos : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 ,FREQ2 = 9, X 3 = 12, FREQ3 = 7, entonces encuentra x = 7.5, Sx =3.745585637, Cax = 0 , y Cpx = 0.503655401Entre dados : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 ,FREQ2 = 9, X 3 = 12, FREQ3 = 7, depois encontre x = 7.5, Sx =3.745585637, Cax = 0 , e Cpx = 0.503655401Geben Sie ein : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 ,FREQ2 = 9, X 3 = 12, FREQ3 = 7, Sie sehen dann x = 7.5, Sx =3.745585637, Cax = 0 , und Cpx = 0.503655401Entrez les données : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 =5 , FREQ2 = 9, X 3 = 12, FREQ3 = 7, puis trouvez x = 7.5, Sx =3.745585637, Cax = 0 , et Cpx = 0.503655401Entrare dato : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 ,FREQ2 = 9, X 3 = 12, FREQ3 = 7, poi trova x = 7.5, Sx =3.745585637, Cax = 0 , e Cpx = 0.503655401Voer de gegevens: X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 =5 , FREQ2 = 9, X 3 = 12, FREQ3 = 7 in, en vind de oplossing x =7.5, Sx = 3.745585637, Cax = 0 en Cpx = 0.503655401Indtast data : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 ,FREQ2 = 9, X 3 = 12, FREQ3 = 7, find så x = 7.5, Sx = 3.745585637,Cax = 0 , og Cpx = 0.503655401
: X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 =5 , FREQ2 = 9, X 3 = 12, FREQ3 = 7, x =7.5, Sx = 3.745585637, Cax = 0 , Cpx = 0.503655401Wprowad dane : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 ,FREQ2 = 9, X 3 = 12, FREQ3 = 7, awwyniku otrzymasz x = 7.5, Sx
= 3.745585637, Cax = 0 , i Cpx = 0.503655401: X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 , FREQ2
= 9, X 3 = 12, FREQ3 = 7, x = 7.5, Sx = 3.745585637, Cax
= 0 ,¥H¤ÎCpx = 0.503655401Masukkan data : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 ,FREQ2 = 9, X 3 = 12, FREQ3 = 7, kemudian carilah x = 7.5, Sx =3.745585637, Cax = 0 , and Cpx = 0.503655401
[ MODE ] 11 - V A R 2 - V A R
DD
R E G
D - C LSTAT
Ex � 33
[ ] [ DATA ] [ ]D A T A � I N P U T
DD
L I M I T
D I S T RSTAT
[ ] 2X L S L = 2
DD STAT
[ ] 13 [ ]X U S L = 13
DD STAT
13.
[ DATA ]D A T A � I N P U T
DD
L I M I T
D I S T RSTAT
[ ] 3X 1 = 3
DD STAT
[ ] 2F R E Q 1 = 2
DD STAT
[ ] 5 [ ] 9 [ ] 12 [ ] 7F R E Q 3 = 7
DD STAT
[ 2nd ] [ STATVAR ]n x S x x
DD
Rx Xmax
CVx XminSTAT
18.
[ ]n x S x x
DD
Rx Xmax
CVx XminSTAT
7.5
[ ]n x S x x
DD
Rx Xmax
CVx XminSTAT
3.745585637
Ex � 34
[ Graph ] [ ]0 N � D I S T
DD
1 H I S T
2 S P CSTAT
[ ]
DD STAT
[ 2nd ] [ STATVAR ] [ ] [ ][ ] [ ] x x 2 Cpkx
DD
Cax Cpx
ppmSTAT
0.
[ ]x x 2 Cpkx
DD
Cax Cpx
ppmSTAT
0.503655401
[ Graph ]0 N � D I S T
DD
1 H I S T
2 S P CSTAT
[ ]
DD STAT
[ 2nd ] [ STATVAR ] [ Graph ] [ ][ ] 0 N � D I S T
DD
1 H I S T
2 S P CSTAT
[ ]
DD STAT
Example 44Enter data : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3, Y 1 = 4,X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, then find out x = 5, Sx = 2, Cax =0, Cay = 0.111111111Entre datos : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3, Y 1 =4, X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, entonces encuentra x = 5, Sx
= 2, Cax = 0, Cay = 0.111111111
Ex � 35
Entre dados : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3, Y 1 =4, X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, depois encontre x = 5, Sx = 2,Cax = 0, Cay = 0.111111111Geben Sie ein : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3, Y
1 = 4, X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, Sie sehen dann x = 5, Sx =2, Cax = 0, Cay = 0.111111111Entrez les données : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 =3, Y 1 = 4, X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, puis trouvez x = 5, Sx
= 2, Cax = 0, Cay = 0.111111111Entrare : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3, Y 1 = 4, X
2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, poi trova x = 5, Sx = 2, Cax = 0, Cay
= 0.111111111Voer de gegevens: X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3,Y 1 = 4, X 2 = 5 , Y 2 = 7, X 3 = 7 en Y 3 = 6 in, en vind de oplossing
x = 5, Sx = 2, Cax = 0, Cay = 0.111111111Indtast data : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3, Y 1 =4, X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, find så x = 5, Sx = 2, Cax = 0,Cay = 0.111111111
: X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3,Y 1 = 4, X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6,
x = 5, Sx = 2, Cax = 0, Cay = 0.111111111Wprowad dane : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3,Y 1 = 4, X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, awwyniku otrzymasz x =5, Sx = 2, Cax = 0, Cay = 0.111111111
: X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3, Y 1 = 4,
X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, x = 5, Sx = 2, Cax = 0,Cay = 0.111111111Masukkan data : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3, Y
1 = 4, X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, kemudian carilah x = 5, Sx
= 2, Cax = 0, Cay = 0.111111111
[ MODE ] 1 [ ]1 - V A R 2 - V A R
DD
R E G
D - C LSTAT
[ ] [ DATA ] [ ]D A T A � I N P U T
DD
L I M I T
D I S T RSTAT
[ ] 2 [ ] 8 [ ] 3 [ ] 9[ ] Y U S L = 9
DD STAT
9.
Ex � 36
[ DATA ]D A T A � I N P U T
DD
L I M I T
D I S T RSTAT
[ ] 3 [ ] 4 [ ] 5 [ ] 7[ ] 7 [ ] 6 Y 3 = 6
DD STAT
[ 2nd ] [ STATVAR ] [ ]n x S x x
DD
Rx Xmax
CVx XminSTAT
5.
[ ]n x S x x
DD
Rx Xmax
CVx XminSTAT
2.
[ ] [ ] [ ] [ ] [ ] [ ][ ] [ ] x x 2 x y
DD
y y 2
Cax CaySTAT
0.
[ ]x x 2 x y
DD
y y 2
Cax CaySTAT
0.111111111
[ Graph ]
DD STAT
Example 45Based on Example 44, change Y1 = 4 as Y1 = 9 and X2 = 5 as X2 =8, then find Sx = 2.645751311Basado en el Ejemplo 44, cambia Y1 = 4 como Y1 = 9 y X2 = 5como X2 = 8, entonces encuentra Sx = 2.645751311Baseado no Exemplo 44, mude Y1 = 4 como Y1 = 9 e X2 = 5 comoX2 = 8, depois encontre Sx = 2.645751311Auf Grund von Beispiel 44, ändem Sie Y1 = 4 zu Y1 = 9 und X2 = 5zu X2 = 8, Sie bekommen Sx = 2.645751311Sur l�Exemple 44, changez Y1 = 4 pour Y1 = 9 et X2 = 5 pour X2 = 8,puis trouvez Sx = 2.645751311Basarsi su Esempio 44, Cambia Y1 = 4 come Y1 = 9 e X2 = 5 comeX2 = 8, poi trova Sx = 2.645751311Gebaseerd op voorbeeld 44, verander Y1 = 4 door Y1 = 9 en X2 =5 door X2 = 8, en vind vervolgens Sx = 2.645751311
Ex � 37
Tag udgangspunkt i eksempel 44, ret Y1 = 4 til Y1 = 9 og X2 = 5 tilX2 = 8, og find så Sx = 2,645751311
44, Y1 = 4 Y1 = 9 X2 =5 X2 = 8, Sx = 2.645751311WPrzyk adzie 44, zamie Y1 = 4 na Y1 = 9 i X2 = 5 na X2 = 8, awwyniku otrzyhmasz Sx = 2.645751311
44 Y1 = 4 Y1 = 9 X2 = 5 X2 = 8,
Sx = 2.645751311Berdasarkan Contoh 44, ubahlah Y1 = 4 menjadi Y1 = 9 dan X2 = 5menjadi X2 = 8, kemudian carilah Sx = 2.645751311
[ DATA ]D A T A � I N P U T
DD
L I M I T
D I S T RSTAT
[ ] [ ] 9Y 1 = 9
DD STAT
[ ] 8X 2 = 8
DD STAT
[ 2nd ] [ STATVAR ] [ ] [ ]n x S x x
DD
R Xmax
CVx XminSTAT
2.645751311
Example 46Enter data : ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9, X 3 =12, FREQ 3 = 7, then find out t = �1.510966203, P ( t ) = 0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346Entre datos : ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9, X 3
= 12, FREQ 3 = 7, entonces encuentra t = �1.510966203, P ( t ) = 0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346Entre dados : ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9, X 3
= 12, FREQ 3 = 7, depois encontre t = �1.510966203, P ( t ) = 0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346Geben Sie ein : ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9, X
3 = 12, FREQ 3 = 7, Sie sehen dann t = �1.510966203, P ( t ) = 0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346Entrez les données : ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2
= 9, X 3 = 12, FREQ 3 = 7, puis trouvez t = �1.510966203, P ( t ) = 0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346
Ex � 38
Entrare dato : ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9, X 3
= 12, FREQ 3 = 7, poi trova t = �1.510966203, P ( t ) = 0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346Voer de gegevens: ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 =9, X 3 = 12, FREQ 3 = 7 in, en vind de oplossing t = �1.510966203, P ( t ) = 0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346Indtast data : ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9, X 3
= 12, FREQ 3 = 7, og find så t = �1.510966203, P ( t ) = 0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346
: ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9,X 3 = 12, FREQ 3 = 7, t = �1.510966203, P ( t ) = 0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346Wprowad dane : ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9,X 3 = 12, FREQ 3 = 7, awwyniku otrzymasz t = �1.510966203, P ( t ) = 0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346
: ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9, X 3 = 12,
FREQ 3 = 7, t = �1.510966203, P ( t ) = 0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346Masukkan data : ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9,X 3 = 12, FREQ 3 = 7, kemudian carilah t = �1.510966203, P ( t ) = 0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346
[ MODE ] 11 - V A R 2 - V A R
DD
R E G
D - C LSTAT
[ ] [ DATA ] [ ] [ ]D A T A � I N P U T
DD
L I M I T
D I S T RSTAT
[ ] 2 [ ] a x = 2
DD STAT
2.
[ DATA ] [ ] 3 [ ] 2 [ ] 5[ ] 9 [ ] 12 [ ] 7 F R E Q 3 = 7
DD STAT
[ 2nd ] [ STATVAR ] [ ]P ( t ) Q ( t )
DD
R ( t ) t�1.510966203
STAT
Ex � 39
[ ]P ( t ) Q ( t )
DD
R ( t ) t0.9346
STAT
[ ]P ( t ) Q ( t )
DD
R ( t ) t0.4346
STAT
[ ]P ( t ) Q ( t )
DD
R ( t ) t0.0654
STAT
Example 47For the following data using linear regression and estimate x � = ? for y = 573 and y� = ? for x = 19
Para los datos siguientes usando regresión lineal y estimación x � =? para y =573 e y � = ? para x = 19
Para os dados seguintes usando regressão linear e estimativa x � =? para y =573 e y � = ? para x = 19
Für die folgenden Daten unter Verwendung der linearenRegression und Schätzung x � = ? für y = 573 und y � = ? für x = 19
Pour les données suivantes utilisez la Régression linéaire etestimez x � =? pour y =573 et y � = ? pour x = 19
Per i seguenti dati usando regressione lineare e stimare x � = ? per y = 573 e y � = ? per x = 19
Voor de volgende gegevens aan de hand van de lineaireregressie en voorspel x ' =? voor y =573 en y ' = ? voor x = 19
Brug lineær regression på de følgende data, og estimer x ' =? fory =573 og y ' = ? for x = 19
x � =? y =573 y � = ? x = 19
Zastosuj regresj liniow dla nast puj cych danych i znajd x � = ? for y = 573 i y � = ? for x = 19
y = 573, x ' = ? x =
19 y ' = ?
Untuk data berikut ini gunakan regresi linear dan estimasikan x '= ? untuk y = 573 dan y ' = ? untuk x = 19
X 15 17 21 28
Y 451 475 525 678
Ex � 40
[ MODE ] 1 [ ]1 - V A R 2 - V A R
DD
R E G
D - C LSTAT
[ ]L I N L O G e
DD
X 2 I N V
Q U A DSTAT
[ ] [ DATA ]D A T A � I N P U T
DD
L I M I T
D I S T RSTAT
[ ] 15 [ ] 451 [ ] 17[ ] 475 [ ] 21 [ ] 525 [ ]28 [ ] 678
Y 4 = 6 7 8
DD STATL I N
[ 2nd ] [ STATVAR ] [ Graph ]
DD STAT
[ 2nd ] [ STATVAR ] [ ] [ ] [ ]a b r x � y �
DD STATL I N
[ ] 573 [ ]x � ( 5 7 3 )
DD STAT
22.56700734
[ 2nd ] [ STATVAR ] [ ] [ ] [ ][ ]
a b r x � y �
DD STATL I N
[ ] 19 [ ]y � ( 1 9 )
DD STAT
510.2658228
Example 48For the following data using quadratic regression and estimate y � = ? for x = 58 and x � = ? for y =143
Ex � 41
Para los datos siguientes usando regresión cuadrática yestimación y � = ? para x = 58 e x � = ? para y = 143 Para os dados seguintes usando regressão quadrática eestimativa y � = ? para x = 573 e x � = ? para y = 143 Für die folgenden Daten unter Verwendung der quadratischenRegression und Schätzung y � = ? für x = 573 und x � = ? für y = 143Pour les données suivantes utilisez la Régression quadratique etestimez y � = ? pour x = 573 et x � = ? pour y = 143 Per i seguenti dati usando regressione quadratica e stimare y �= ? per x = 56 e x �= ? per y = 143 Voor de volgende gegevens aan de hand van de kwadratischeregressie en voorspel y ' = ? voor x = 58 en x ' =? voor y =143Brug kvadratregression på de følgende data, og estimer y ' = ? forx = 58 og x ' =? for y =143
y � =? x = 573 x � = ? y = 143Zastosuj regresj liniow dla nast puj cych danych i znajd y � =? for x = 573 i x � = ? for y = 143
x = 58, y ' = ? y =
143 x ' = ?Untuk data berikut ini gunakan regresi kuadratik dan estimasikanx ' = ? untuk y 58 dan y ' = ? untuk x =143
X 57 61 67
Y 101 117 155
[ MODE ] 1 [ ]1 - V A R 2 - V A R
DD
R E G
D - C LSTAT
[ ] [ ] [ ]L I N L O G e
DD
X 2 I N V
Q U A DSTAT
[ ] [ DATA ]D A T A � I N P U T
DD
L I M I T
D I S T RSTAT
[ ] 57 [ ] 101 [ ] 61[ ] 117 [ ] 67 [ ] 155 Y 3 = 1 5 5
DD STATQ U A D
Ex � 42
[ 2nd ] [ STATVAR ] [ Graph ]
DD STAT
[ 2nd ] [ STATVAR ] [ ] [ ] [ ]a b c x � y �
DD STATQUAD
[ ] 143 [ ]x 1 x 2
DD STAT
65.36790453QUAD
[ ]x 1 x 2
DD STAT
35.48923833QUAD
[ 2nd ] [ STATVAR ] [ ] [ ] [ ][ ]
a b c x � y �
DD STATQUAD
[ ] 58 [ ]y � ( 5 8 )
DD STAT
104.3
Example 4931 10 = 1F16 = 11111 2 = 37 8
[ MODE ] 2
d
31 [ ]d 3 1
d
31
[ dhbo ]D H B O
d
31
Ex � 43
[ ]D H B O
h
1F
[ ]D H B O
b
11111
[ ]D H B O
o
37
Example 504777 10 = 1001010101001 2
[ MODE ] 2 [ dhbo ] [ ] [ ]D E C H E X B I N
O C T o
d h b
o
[ ] [ dhbo ] [ ] [ ]D E C H E X B I N
O C T o
d h b
b
[ ] 4777 [ ]d 4 7 7 7
1b
10101001
[ ]d 4 7 7 7
2b
10010
[ ]d 4 7 7 7
3b
0
[ ]d 4 7 7 7
4b
0
Example 51
Ex � 44
How is 3A 16 expressed as a negative ? Ans : FFFFFFC6Cómo se expresa 3A 16 comoun negativo ? Resp : FFFFFFC6Como se expressa 3A 16 como um negativo ? Resp : FFFFFFC6Wie wird 3A 16 negativ ausgedrückt ? Ant : FFFFFFC6Comment 3A 16 est-il exprimé en tant que négative ? Rép :FFFFFFC6Come è 3A 16 è espresso come un negativo ? Risp : FFFFFFC6Hoe wordt 3 A 16 voorgesteld als een negatief getal? Antwoord :FFFFFFC6Hvordan udtrykkes 3A 16 som et negativt tal ? Svar : FFFFFFC6
3A 16 ? : FFFFFFC6Wjaki sposób mo na przedstwi liczb 3A16 jako liczb ujemn ?Odp : FFFFFFC63A 16 : FFFFFFC6Bagaimanakah cara mengekspresikan negatif dari 3A 16 ? Jawab :FFFFFFC6
[ MODE ] 2 [ dhbo ] [ ]D E C H E X B I N
O C T o
d h b
b
[ ] [ NEG ] 3 /A [ ]N E G h 3 /A
h
FFFFFFC6
Example 521234 10 + 1EF 16 ) 24 8 = 2352 8 = 1258 10
[ MODE ] 2 [ dhbo ] [ ]D E C H E X B I N
O C T o
d h b
h
[ ] [ dhbo ] [ ] [ ]D E C H E X B I N
O C T o
d h b
o
[ ] 1234 [ + ]d 1 2 3 4 +
o
[ dhbo ] [ ] [ ] [ ]D E C H E X B I N
O C T o
d h b
o
Ex � 45
[ ] 1IEIF [ ) ]d 1 2 3 4 + h 1IEIF /
o
[ dhbo ] [ ] [ ]D E C H E X B I N
O C T o
d h b
o
[ ] 243 4 + h 1IEIF / O 24
o
[ ]d 1 2 3 4 + h 1IEIF /
o
2352
[ dhbo ] [ ] [ ] [ ]D H B O
d
1258
Example 531010 2 AND ( A 16 OR 7 16 ) = 1010 2 = 10 10
[ MODE ] 2 [ dhbo ] [ ] [ ]D E C H E X B I N
O C T o
d h b
d
[ ] [ dhbo ] [ ] [ ] [ ][ ] D E C H E X B I N
O C T o
d h b
b
[ ] 1010 [ AND ] [ ( ) ]1 0 1 0 A N D (
b
[ dhbo ] [ ] [ ] [ ]D E C H E X B I N
O C T o
d h b
b
Ex � 46
[ ] /A [ OR ] [ dhbo ] [ ][ ] [ ] D E C H E X B I N
O C T o
d h b
b
[ ] 7 [ ]b 1 0 1 0 A N D (
b
1010
[ dhbo ] [ ] [ ]D H B O
d
10
Example 54Create a program to preform arithmetic calculation for complexnumbersCree un programa para realizar el cálculo aritmético de númeroscomplejosCrie um programa para executar cálculo aritmético para númeroscomplexosErstellen Sie ein Programm, um arithmetische Berechnungen fürkomplexe ZahlenCréez un progeamme pour accomplir des calculs arithmétiquespour des nombres complexesGenerare un programma per effettuare calcoli aritmetici pernumeri complessi (Descrizione)Creëer een programma om een wiskundige berekening metcomplexe nummers uit te voeren.Opret et program, der udfører aritmetiske beregninger forkomplekse tal
Napisz program przeprowadzania oblicze arytmetycznych liczbzespolonych
Buatlah sebuah program untuk menjalankan perhitunganaritmetika untuk bilangan kompleks
Z 1 = A + B i, Z 2 = C + D i� Sum : Z 1 + Z 2 = ( A + B ) + ( C + D ) i � Difference : Z 1 � Z 2 = ( A � B ) + ( C � D ) i � Product : Z 1 x Z 2 = E + F i = ( AC � BD ) + ( AD + BC ) i
� Quotient : Z 1 Z 2 = E + F i =
Ex � 47
Program Type : MAIN
Line Program
1 L b l 0 :
2 P R I N T " C H O O S E T H E O P E R A T
O R " ; S L E E P ( 5 ) ;
3 P R I N T " 1 : + 2 : � 3 : 4 : / " ;
4 I N P U T O ;
5 I F ( O > 4 ) T H E N { G O T O 0 ; }
6 I N P U T A , B , C , D ;
7 I F ( O == 1 ) T H E N { G O T O 3 ; }
8 I F ( O == 2 ) T H E N { G O T O 2 ; }
9 I F ( O == 3 ) T H E N { G O T O 1 ; }
10 E L S E { E = ( A C + B D ) / ( C 2 + D 2 )
11 F = ( B C � A D ) / ( C 2 + D 2 ) }
12 G O T O 4 ;
13 L b l 1 :
14 E = ( A C � B D ) ; F = ( A D + B C )
15 G O T O 4 ;
16 L b l 2 :
17 E = ( A � C ) ; F = ( B � D ) ; G O T O 4 ;
18 L b l 3 :
19 E = ( A + C ) ; F = ( B + D ) ; G O T O 4 ;
20 L b l 4 :
21 Q = A B S ( F )
22 I F ( F > 0 ) T H E N { P R I N T E , " + " ,
Q , " I " ; }
23 I F ( F < 0 ) T H E N { P R I N T E , " � " ,
Q , " I " ; }
24 E N D
RUN
When the message � 1: +, 2 : � , 3 : x , 4 : / � appears on the display, you can input a � O � value to any of the following values for specifying the type of operation to be performed.Cuando aparezca el mensaje � 1: +, 2 : � , 3 : x , 4 : / � en la pantalla, se puede introducir un valor � O � en cualquiera de los valores siguientes para especificar el tipo de operación a realizar.Quando a mensagem � 1: +, 2 : � , 3 : x , 4 : / � aparecer na tela, você pode entrar um valor � O � a quaisqer dos valores seguintes para especificar o tipo de operação a ser executado.Wenn die Meldung � 1: +, 2 : � , 3 : x , 4 : / � Auf dem Bildschirm erscheint, können Sie einen � O � Wert zu jedem der folgenden Werte eingeben zur Spezifizierung der auszuführendenOperationsart.
Ex � 48
Lorsque le message � 1: +, 2 : � , 3 : x , 4 : / � s�affiche, vous pouvez entrer une valeur � O � à chacune des valeurs suivantes pour spécifier le type d�opération à accomplir. Quando compare il messaggio � 1: +, 2 : � , 3 : x , 4 : / � sul display, si può immettere un valore �0� ad uno dei seguenti valori per specificare il tipo di operazione da effettuare.Wanneer het bericht � 1: +, 2 : � , 3 : x , 4 : / � op het beeldscherm verschijnt, Wanneer het bericht " 1: A(N), 2 :S(N) " op hetbeeldscherm verschijnt, kunt u een "O" waarde toekennen aan devolgende waarden om het type van bewerking op te geven die zaluitgevoerd worden.Når meddelelsen � 1: +, 2 : � , 3 : x , 4 : / � vises på displayet, kan du indtaste en værdi " O " for hver af de følgende værdier for atangive, hvilken type operation der skal udføres.
� 1: +, 2 : � , 3 : x , 4 : / �, � O �
, .Je li pojawi si komunikat � 1: +, 2 : � , 3 : x , 4 : / �, to mo nanada warto � O � dowolnej z nast puj cych wielko ci, abywybra typ operacji, która ma by wykonana.
� 1: +, 2 : � , 3 : x , 4 : / � � O �
Jika pesan � 1: +, 2 : � , 3 : x , 4 : / � muncul di layar, Anda dapat memasukkan nilai "O " ke salah satu dari nilai-nilai berikut iniuntuk menentukan tipe operasi yang akan dijalankan.
1.... Z 1 + Z 2 2.... Z 1 � Z 2 3.... Z 1 x Z 2 4.... Z 1 ) Z 2
Z 1 = A + B i = 17 + 5 i
Z 2 = C + D i = ( � 3 ) + 14 iZ 1 + Z 2 =14 + 19 i
[ ] ( 5 Seconds )C H O O S E T H E
PROGDD
1 : + 2 : � 3 :
PROGDD
[ ] 1O = 1
PROGDD
Ex � 49
[ ] 17 [ ] 5 [ ][ ( � ) ] 3 [ ] 14 D = 1 4
PROGDD
[ ]1 4 + 1 9 I
PROGDD
Z 1 = A + B i = 10 + 13 i
Z 2 = C + D i = 6 + 17 iZ 1 � Z 2 = 4 � 4 i
[ ] ( 5 Seconds )C H O O S E T H E
PROGDD
1 : + 2 : � 3 :
PROGDD
[ ] 2O = 2
PROGDD
[ ] 10 [ ] 13 [ ][ ( � ) ] 6 [ ]17 D = 1 7
PROGDD
[ ]4 � 4 I
PROGDD
Z 1 = A + B i = 2 + ( � 5 ) i
Z 2 = C + D i = 11 + 17 iZ 1 x Z 2 = 107 � 21 i
[ ] ( 5 Seconds )C H O O S E T H E
PROGDD
Ex � 50
1 : + 2 : � 3 :
PROGDD
[ ] 3O = 3
PROGDD
[ ] 2 [ ] [ ( � ) ] 5 [ ] 11 [ ] 17 D = 1 7
PROGDD
[ ]1 0 7 � 2 1 I
PROGDD
Z 1 = A + B i = 6 + 5 i
Z 2 = C + D i = ( � 3 ) + 4 i
Z 1
Z 2
= 0.08 � 1.56 i
[ ] ( 5 Seconds )C H O O S E T H E
PROGDD
1 : + 2 : � 3 :
PROGDD
[ ] 4O = 4
PROGDD
[ ] 6 [ ] 5 [ ][ ( � ) ] 3 [ ] 4 D = 4
PROGDD
[ ]0. 0 8 � 1. 5 6 I
PROGDD
Example 55
Ex � 51
Create a program to determine solutions for quadratic equationCree un programa para determinar las soluciones de la ecuacioncuadráticaCrie um programa para determinar soluções para equaçãoquadráticaErstellen sie ein Programm, um die Lösungen für quadratischeGleichungen zu bestimmenCréez un programme pour déterminer les solutions pour uneéquation quadratiqueGenerare un programma per determinare le soluzioni diun�equazione quadratica Creëer een programma om een kwadratische vergelijking op telossenOpret et program, der finder løsninger for andengradsligninger
Napisz program pozwalaj cy rozwi zywa równania kwadratowe
Membuat sebuah program untuk menentukan penyelesaian daripersamaan kuadratik
A X2
+ B X + C = 0, D = B2 � 4AC
1) D > 0 ,
2) D = 0
3) D < 0 ,
Program Type : MAIN
Line Program
1 I N P U T A , B , C ;
2 D = B 2 � 4 A C
3 E = � B / 2 A ; F = ( A B S ( D ) ) / 2 A
4 G = E + F ; H = E � F
5 I F ( D > 0 ) T H E N { P R I N T " X 1 = " ,
G , " X 2 = " , H ; }
6 I F ( D == 0 ) T H E N { P R I N T " X = " , E
; }
7 I F ( D < 0 ) T H E N { P R I N T " X 1 = " ,
E , " + " , F , " I " , " X 2 = " , E , " � "
, F , " I " ; }
8 E N D
RUN
2 X 2 � 7 X + 5 = 0 X 1 = 2.5 , X 2 = 1
[ ]A =
PROGDD
Ex � 52
2 [ ] [ (�) ] 7 [ ] 5C = 5
PROGDD
[ ]X 1 = 2 . 5 X 2 = 1
PROGDD
25 X2 � 70 X + 49 = 0 X = 1.4
[ ]A =
PROGDD
25 [ ] [ (�) ] 70 [ ] 49C = 4 9
PROGDD
[ ]X = 1 . 4
PROGDD
X2
+ 2 X + 5 = 0 X 1 = � 1 + 2 i, X 2 = � 1 � 2 i
[ ]A =
PROGDD
1 [ ] 2 [ ] 5C = 5
PROGDD
[ ]X 1 = � 1 + 2 I X 2
PROGDD
[ ] [ ] [ ] [ ] [ ] [ ][ ] [ ] [ ] [ ] [ ] [ ][ ] [ ] [ ] [ ] [ ] [ ][ ] [ ]
2 I X 2 = � 1 � 2 I
PROGDD
Example 56
Ex � 53
Create a program for common difference sequence and numbers( A : First item, D : Common difference, N : number )Cree un programa para la secuencia de progresión aritmética ynúmeros ( A : Primer elemento, D : Diferencia común, N :número )Crie um programa para sequências e números de diferençacomum ( A : Primeiro item, D : Diferença comum, N : número )Erstellen Sie ein Programm für normale Differenzsequenzen undZahlen ( A : Erster Punkt, D : Allgemeine Differenz, N : Zahl )Créez un programme pour une séquence de différence communeet les nombres ( A : Premier objet D : Différence commun, N :nombre )Generare un programma per numeri e sequenze di differenzecomuni / (Descrizione) : A : Primo oggetto, D : Differenza comune,N : numero,Creëer een programma voor het berekenen van het gemeenverschil en getallen ( A : eerste item, D : Gemeen verschil, N :getal)Opret et program for fælles differensfølger og tal ( A : førsteelement, D : fælles differens, N : tal )
( A : , D : , N :)
Napisz program do analizy post pu arytmetycznego ( A :Pierwszy wyraz, D : Ró nica post pu, N : wyraz ogólny )
(A : , D : , N : )Membuat sebuah program untuk urutan perbedaan umum danbilangan-bilangan ( A : Item pertama, D : Perbedaan umum, N :bilangan )
Sum : S ( N ) = A+(A+D)+(A+2D)+(A+3D)+...
=
Nth item : A ( N ) = A+ (N �1)D
Program Type : MAIN
Line Program
1 P R I N T " 1 : A ( N ) 2 : S ( N ) " ; S L
E E P ( 5 ) ;
2 I N P U T P , A , D , N ;
3 I F ( P == 1 ) T H E N { G O T O 1 ; }
4 S = N ( 2 A + ( N � 1 ) D ) / 2
5 P R I N T " S ( N ) = " , S ;
6 G O T O 2 ;
7 L b l 1 :
8 T = A + ( N � 1 ) D
9 P R I N T " A ( N ) = " , T ;
10 L b l 2 : E N D
RUN
Ex � 54
When the message � 1: A(N), 2 :S(N) � appears on the display, you can input a � P � value to any of the following values for specifying the type of operation to be performed.Cuando aparezca el mensaje � 1: A(N), 2 :S(N) � en la pantalla, se puede introducir un valor � P � en cualquiera de los valores siguientes para especificar el tipo de operación a realizar.Quando a mensagem � 1: A(N), 2 :S(N) � aparecer na tela, você pode entrar um valor � P � a quaisqer dos valores seguintes para especificar o tipo de operação a ser executado.Wenn die Meldung � 1: A(N), 2 :S(N) � Auf dem Bildschirm erscheint, können Sie einen � P � Wert zu jedem der folgenden Werte eingeben zur Spezifizierung der auszuführendenOperationsart.Lorsque le message � 1: A(N), 2 :S(N) � s�affiche, vous pouvez entrer une valeur � P � à chacune des valeurs suivantes pour spécifier le type d�opération à accomplir. Quando compare il messaggio � 1: A(N), 2 :S(N) � sul display, si può immettere un valore � P � ad uno dei seguenti valori per specificare il tipo di operazione da effettuare.Wanneer het bericht � 1: A(N), 2 :S(N) � op het beeldscherm verschijnt, kunt u een " P " waarde toekennen aan de volgendewaarden om het type van bewerking op te geven die zaluitgevoerd worden.Når meddelelsen � 1: A(N), 2 :S(N) � vises på displayet, kan du indtaste en værdi " P " for hver af de følgende værdier for atangive, hvilken type operation der skal udføres.
� 1: A(N), 2 :S(N) �, � P �
, .Je li pojawi si komunikat � 1: A(N), 2 :S(N) �, to mo na nadawarto � P � dowolnej z nast puj cych wielko ci, aby wybra typoperacji, która ma by wykonana.
� 1: A(N), 2 :S(N) � � P �
Jika pesan � 1: A(N), 2 :S(N) � muncul di layar, Anda dapat memasukkan nilai " P " ke salah satu dari nilai-nilai berikut iniuntuk menentukan tipe operasi yang akan dijalankan.
1.... A(N) 2.... S(N)
A = 3 , D = 2, N = 4 A (N) = A (4) = 9
[ ] ( 5 Seconds )1 : A ( N ) 2 : S (
PROGDD
P =
PROGDD
Ex � 55
1 [ ] 3 [ ] 2 [ ]4 N = 1
PROGDD
[ ]A ( N ) = 9
PROGDD
A = 3 , D = 2, N = 12 S (N) = S (12) = 168
[ ] ( 5 Seconds )1 : A ( N ) 2 : S (
PROGDD
P =
PROGDD
2 [ ] 3 [ ] 2 [ ]12 N = 1 2
PROGDD
[ ]S ( N ) = 1 6 8
PROGDD
Example 57Create a program for common ratio sequence and numbers( A :First item, R : common ratio, N : number )Cree un programa para la secuencia progresión geomética ynúmeros( A : Primer elemento, R : progresión geomética, N :número )Crie um programa para sequências e números de razãocomum( A : Primeiro item, R : razão comum, N : número )Erstellen Sie ein Programm für häufige Verhältnissequenzen undZahlen ( A : Erster Punkt, R : häufige Verhältnissequenzen, N :Zahl )Créez un programme pour une séquence de taux commun et lesnombres( A : Premier objet R : Taux commun, N : nombre )Generare un programma per numeri e sequenze di rapportocomune A : Primo oggetto, R : rapporto comune, N : numeroCreëer een programma voor het berekenen van degemeenschappelijke factor en getallen ( A : eerste item, R :gemene factor, N : getal)
Ex � 56
Opret et program for fælles brøkfølger og tal ( A : første element,R : fælles brøk, N : tal )
( A : , R : , N :)
Napisz program do analizy post pu geometrycznego( A :Pierwszy wyraz, R : iloraz post pu, N : wyraz ogólny )
(A : , R : , N : )Membuat sebuah program untuk urutan rasio umum danbilangan-bilangan ( A : Item pertama, R : rasio umum, N :bilangan )
Sum : S ( N ) = A+AR+AR2+AR
3....
1) R 1
2) R =1 A ( N ) = AR (N �1) Nth item : A ( N ) = A (N �1)
Program Type : MAIN
Line Program
1 P R I N T " 1 : A ( N ) 2 : S ( N ) " ; S L
E E P ( 5 ) ;
2 I N P U T P , A , R , N ;
3 I F ( P == 1 ) T H E N { G O T O 1 ; }
4 I F ( R == 1 ) T H E N { S = A N }
5 I F ( R 1 ) T H E N { S = A ( R ^ N � 1 ) / (
R � 1 ) }
6 P R I N T " S ( N ) = " , S ;
7 G O T O 2 ;
8 L b l 1 :
9 T = A R ^ ( N � 1 )
10 P R I N T " A ( N ) = " , T ;
11 L b l 2 : E N D
RUN
When the message � 1: A(N), 2 :S(N) � appears on the display, you can input a � P � value to any of the following values for specifying the type of operation to be performed.Cuando aparezca el mensaje � 1: A(N), 2 :S(N) � en la pantalla, se puede introducir un valor � P � en cualquiera de los valores siguientes para especificar el tipo de operación a realizar.Quando a mensagem � 1: A(N), 2 :S(N) � aparecer na tela, você pode entrar um valor � P � a quaisqer dos valores seguintes para especificar o tipo de operação a ser executado.Wenn die Meldung � 1: A(N), 2 :S(N) � Auf dem Bildschirm erscheint, können Sie einen � P � Wert zu jedem der folgenden Werte eingeben zur Spezifizierung der auszuführendenOperationsart.
Ex � 57
Lorsque le message � 1: A(N), 2 :S(N) � s�affiche, vous pouvez entrer une valeur � P � à chacune des valeurs suivantes pour spécifier le type d�opération à accomplir. Quando compare il messaggio � 1: A(N), 2 :S(N) � sul display, si può immettere un valore � P � ad uno dei seguenti valori per specificare il tipo di operazione da effettuare.Wanneer het bericht � 1: A(N), 2 :S(N) � op het beeldscherm verschijnt, kunt u een " P " waarde toekennen aan de volgendewaarden om het type van bewerking op te geven die zaluitgevoerd worden.Når meddelelsen � 1: A(N), 2 :S(N) � vises på displayet, kan du indtaste en værdi " P " for hver af de følgende værdier for atangive, hvilken type operation der skal udføres.
� 1: A(N), 2 :S(N) �, � P �
, .Je li pojawi si komunikat � 1: A(N), 2 :S(N) �, to mo na nadawarto � P � dowolnej z nast puj cych wielko ci, aby wybra typoperacji, która ma by wykonana.
� 1: A(N), 2 :S(N) � � P �
Jika pesan � 1: A(N), 2 :S(N) � muncul di layar, Anda dapat memasukkan nilai " P " ke salah satu dari nilai-nilai berikut iniuntuk menentukan tipe operasi yang akan dijalankan.
1.... A(N) 2.... S(N)
A = 5, R = 4, N = 7 A (N) = A (7) = 20480
[ ] ( 5 Seconds )1 : A ( N ) 2 : S (
PROGDD
P =
PROGDD
1 [ ] 5 [ ] 4 [ ]7 N = 7
PROGDD
[ ]A ( N ) = 2 0 4 8 0
PROGDD
A = 5, R = 4, N = 9 S (N) = S (9) = 436905
Ex � 58
[ ] ( 5 Seconds )1 : A ( N ) 2 : S (
PROGDD
P =
PROGDD
2 [ ] 5 [ ] 4 [ ]9 N = 9
PROGDD
[ ]S ( N ) = 4 3 6 9 0 5
PROGDD
A = 7, R = 1, N = 14 S (N) = S (14) = 98
[ ] ( 5 Seconds )1 : A ( N ) 2 : S (
PROGDD
P =
PROGDD
2 [ ] 7 [ ] 1 [ ]14 N = 1 4
PROGDD
[ ]S ( N ) = 9 8
PROGDD
Example 58Create a program to determine solutions for variable linearequation.Cree un programa para determinar las soluciones de unaecuación lineal variable.Crie um programa para determinar soluções para equação linearvariável.
Ex � 59
Erstellen Sie ein Programm, um Lösungen für eine variablelineare Gleichung zu bestimmen.Créez un programme pour déterminer les solutions pour uneéquation linéaire variableGenerare un programma per determinare le soluzioni diequazioni lineari variabiliCreëer een programma voor het berekenen van een variabelelineaire vergelijking.Opret et program, der finder løsninger for variable lineæreligninger
.Napisz program pozwalaj cy rozwi zywa równania liniowe
Membuat sebuah program untuk menentukan penyelesaian daripersamaan kuadratik
Program Type : MAIN
Line Program
1 I N P U T A , B , C , D , E , F ;
2 G = A B S ( A ) / A B S ( D )
3 D = D G ; E = E G ; F = F G
4 I F ( A == D ) T H E N { G O T O 1 ; }
5 H = ( C + F ) / ( B + E )
6 G O T O 2 ;
7 L b l 1 :
8 H = ( C � F ) / ( B � E )
9 L b l 2 :
10 A = ( C � B H ) / A
11 P R I N T " A N S = " ;
12 P R I N T " X = " , A , " Y = " , H ;
13 E N D
RUN
[ ]A =
PROGDD
4A = 4
PROGDD
Ex � 60
[ ] [ ( � ) ] 1 [ ] 30[ ] 5 [ ] 9 [ ]17
F = 1 7
PROGDD
[ ]X = 7 Y = � 2
PROGDD
Example 59Create three subroutines to store the below formulas and useGOSUB-PROG command to write a mainroutine for executing.( Subroutine 1~3 )Cree tres subrutinas para almacenar las fórmulas de másadelante y use el comando GOSUB-PROG para escribir unarutina principal para ejecutar. ( Subrutina 1~3 )Crie três sub-rotinas para armazenar as fórmulas abaixo e usecomando GOSUB-PROG para escrever uma rotina pricipal paraexecução. ( Sub-rotina 1~3 )Erstellen Sie drei Unterprogramme zur Speicherung der untengenannten Formeln und verwenden Sie den GOSUB-PROGBefehl, um ein Hauptprogramm zur Ausführung. ( Unterprogramm1~3 zu schreiben )Créez trois sous-routines pour enregistrer les formulesci-dessous et utilisez la commande GOSUB-PROG pour écrireune routine principale pour l�exécution. ( Sous-routine 1~3 ) Generare tre sottoroutine per memorizzare le seguenti formule eusare il comando GOSUB-PROG per scrivere un routineprincipale per esecuzione/sottoroutine 1~3Creëer drie subroutines om de onderstaande formules op te slaanen gebruik GOSUBS�PROG opdrachten om een hoofdprogramma te creëren voor het uitvoeren van deze subroutines. ( Subroutine1~3 )Opret tre subrutiner til at opbevare formlerne nedenfor, og brugkommandoen GOSUB-PROG til at skrive en hovedrutine, der stårfor afviklingen. ( Subrutine 1~3 )
GOSUB-PROG.
( 1~3 )Napisz trzy podprogramy do przechowywania poni szych wzorówi uæyj polecenia GOSUB-PROG do napisania programug ównego. ( Podprogram 1~3 )
GOSUB-PROG
( 1~3)Membuat tiga subrutin untuk menyimpan rumus-rumus di bawahini dan menggunakan perintah GOSUB-PROG sebagai tempatmenuliskan rutin utama untuk mengeksekusi. ( Subrutin 1~3 )
Ex � 61
Subroutine 1 : CHARGE = N x 3Subroutine 2 : POWER = I ) ASubroutine 3 : VOLTAGE = I ) ( B x Q x A )
Program Type : MAIN
Line Program Note : Subroutine
1 Q = N 3
2 P R I N T " C H A R G E = " , Q ; S L E E P (5 ) ;
3 E N D
Program Type : MAIN
Line Program Note : Subroutine
1 J = I / A2 P R I N T " P O W E R = " , J ; S L E E P ( 5
) ;
3 E N D
Program Type : MAIN
Line Program Note : Subroutine
1 V = I / ( B Q A )
2 P R I N T " V O L T A G E = " , V ;
3 E N D
Program Type : MAIN
Line Program Note : Mainroutine
1 I N P U T N ;
2 G O S U B P R O G 1 ;
3 I N P U T I , A ;
4 G O S U B P R O G 2 ;
5 B = 2 76 G O S U B P R O G 3 ;
7 E N D
RUN
N = 1.5, I = 486, A = 2 CHARGE = 4.5, POWER = 243,VOLTAGE = 2
[ ]N =
PROGDD
1.5N = 1 . 5
PROGDD
Ex � 62
[ ] ( 5 Seconds )C H A R G E = 4 . 5
PROGDD
486I = 4 8 6
PROGDD
[ ] 2A = 2
PROGDD
[ ] ( 5 Seconds )P O W E R = 2 4 3
PROGDD
V O L T A G E = 2
PROGDD
Example 60
Create a program that draws Graph Y = � and Graph Y
= 2 X with Range : X min = � 3.4, X max = 3.4, X scl = 1, Y min = � 3, Y max = 3, Y scl = 1
Cree un programa que dibuje el Gráfico Y = � el
Gráfico Y = 2 X con Rango: X min = � 3.4, X max = 3.4, X scl = 1,Y min = � 3,Y max = 3, Y scl = 1
Crie um programa que desenhe Gráfico Y = � e
Gráfico Y = 2 X com Variação : X min = � 3.4, X max = 3.4, X scl = 1,Y min = � 3,Y max = 3, Y scl = 1
Erstellen Sie ein Programm, das den Graph Y = � und
Graph Y = 2 X mit Bereich : X min = � 3.4, X max = 3.4, X scl = 1, Y min = � 3, Y max = 3, Y scl = 1
Créez un programme qui dessine un Graphique Y = �
et un Graphique Y = 2 X avec l�Étendue : X min = � 3.4, X max = 3.4, X scl = 1, Y min = � 3, Y max = 3, Y scl = 1
Generare un programma che disegni Grafico Y = � e
Grafico Y=2 x con Intervallo : X min = � 3.4, X max = 3.4, X scl =1, Y min = �3, Y max = 3, Y scl =1
Creëer een programma dat de grafiek Y = � en de
grafiek Y = 2 X tekent met een bereik van: X min = � 3.4, X max = 3.4, X scl = 1, Y min = � 3, Y max = 3 en Y scl = 1
Ex � 63
Opret et program, der tegner Graf Y = � og Graf Y = 2
X med intervallet : X min = � 3.4, X maks = 3.4, X scl = 1, Y min = � 3, Y maks = 3, Y scl = 1
Graph Y
= � Graph Y = 2 X : X min = � 3.4, X max
= 3.4, X scl = 1, Y min = � 3, Y max = 3, Y scl = 1
Napisz program do wy wietlania wykresu Y = � oraz
wykresu Y = 2 X w granicach : X min = � 3.4, X max = 3.4, X scl = 1, Y min = � 3, Y max = 3, Y scl = 1
Y = � Y = 2 X
: X min = � 3.4, X max = 3.4, X scl = 1, Y min = � 3, Y max = 3, Y scl = 1Membuat sebuah program untuk menggambar Grafik Y
= � dan Grafik Y = 2 X dengan Kisaran : X min = � 3.4,
X max = 3.4, X scl = 1, Y min = � 3, Y max = 3, Y scl = 1
Program Type : MAIN
Line Program
1 R A N G E ( � 3 . 4 , 3 . 4 , 1 , � 3 , 3 , 1 )
;
2 G r a p h Y = � ( 9 � X 2 )
3 G r a p h Y = 2 X
4 E N D
RUN
[ ]
PROG
n
DD
[ G T ]
PROGDD
Example 61Use FOR command to calculate 1 + 6 = ? , 1 + 5 = ? , 1 + 4 = ?, 2+ 6 = ?, 2 + 5 = ? 2 + 4 = ?Use el comando FOR para calcular 1 + 6 = ? , 1 + 5 = ? , 1 + 4 = ?,2 + 6 = ?, 2 + 5 = ? 2 + 4 = ?Use comando FOR para calcular 1 + 6 = ? , 1 + 5 = ? , 1 + 4 = ?, 2+ 6 = ?, 2 + 5 = ? 2 + 4 = ?Verwenden Sie den FOR Befehl, um 1 + 6 = ? , 1 + 5 = ? , 1 + 4= ?, 2 + 6 = ?, 2 + 5 = ? 2 + 4 = ? zu berechnen
Ex � 64
Utilisez la commande FOR pour calculer 1 + 6 = ? , 1 + 5 = ? , 1 +4 = ?, 2 + 6 = ?, 2 + 5 = ? 2 + 4 = ?Usare il comando FOR per calcolare 1 + 6 = ? , 1 + 5 = ? , 1 + 4= ?, 2 + 6 = ?, 2 + 5 = ? , 2 + 4 = ?Gebruik een FOR-opdracht om een programma te creëren dat 1 +6 = ? , 1 + 5 = ? 1 + 4 = ?, 2 + 6 = ?, 2 + 5 = ? 2 + 4 = ? berekent.Brug FOR-kommandoen til at beregne 1 + 6 = ? , 1 + 5 = ? , 1 + 4= ?, 2 + 6 = ?, 2 + 5 = ? 2 + 4 = ?
FOR 1 + 6 = ? , 1 + 5 = ? , 1 +4 = ?, 2 + 6 = ?, 2 + 5 = ? 2 + 4 = ?U yj polecenia FOR do obliczenia 1 + 6 = ? , 1 + 5 = ? , 1 + 4 = ?,2 + 6 = ?, 2 + 5 = ? 2 + 4 = ?
FOR 1 + 6 = ? , 1 + 5 = ? , 1 + 4 = ?, 2 + 6 = ?, 2 +5 = ? 2 + 4 = ?Gunakan perintah FOR untuk menghitung 1 + 6 = ? , 1 + 5 = ? , 1+ 4 = ?, 2 + 6 = ?, 2 + 5 = ? 2 + 4 = ?
Program Type : MAIN
Line Program
1 C L S ;
2 F O R ( A = 1 ; A 2 ; A ++ ) {
3 F O R ( B = 6 ; B 4 ; B � � )
4 { C = A + B ; P R I N T A , " + " , B , " = "
, C ; } }
5 E N D
RUN
[ ]1 + 6 = 7
PROGDD
1 + 5 = 6
PROGDD
1 + 4 = 5
PROGDD
2 + 6 = 8
PROGDD
Ex � 65
2 + 5 = 7
PROGDD
2 + 4 = 6
PROGDD
Example 62Set the program type of the program area as � BaseN � and calculate the following question :Establezca el tipo de programa de la zona de programa como� BaseN � y calcule la siguiente cuestión : fixe o tipo de programa da área de programa como � BaseN � e calcule a seguinte questão :Setzen Sie die Programmart des Programmbereichs als � BaseN � und berechnen Sie die folgende Frage :Spécifiez le type de programme de la zone de programme en tantque � BaseN � et calculez la question suivante : Regolare il tipo di programma della zona di programma come� BaseN� e calcolare la seguente domanda : Stel het programmatype van het programmageheugen in op "Base�n " en creëer een programma dat de volgende vraag oplost: Indstil programområdet til " BaseN ", og beregn følgendespørgsmål :
� BaseN � :Wejd do trybu � BaseN � i przeprowad nast puj ce obliczenia :
� BaseN � :Tetapkan tipe dari wilayah program sebagai � BaseN � dan hitunglah soal di bawah ini :
ANS = 1010 2 AND ( Y OR 7 16 )
Program Type : BaseN ( DEC )
Line Program
1 I N P U T Y ;
2 C = b 1 0 1 0 A N D ( Y O R h 7 )
3 P R I N T " A N S = " , C ;
4 E N D
RUN
If Y = /A 16 , Ans = 10 10
[ ]Y =
PROG
d
Ex � 66
[ dhbo ] [ ] [ ] [ ]D E C H E X B I N
O C T o
d h b
d
PROG
[ ] / AY = h / A
PROG
d
[ ]A N S = 1 0
PROG
d
If Y =11011 8, Ans = 1010 2
[ ]I N P U T Y
E D I T :
D E C
112
PROG
[ ] [ dhbo ] [ ] [ ]D E C H E X B I N
O C T o
d h b
d
PROG
[ ]I N P U T Y
E D I T :
B I N
112
PROG
RUN
If Y =11011 8, Ans = 1010 2
[ ]Y =
PROG
b
[ dhbo ] [ ] [ ]D E C H E X B I N
O C T o
d h b
b
PROG
[ ] 11011Y = o 1 1 0 1 1
PROG
b
Ex � 67
[ ]A N S = 1 0 1 0
PROG
b
Example 63Create a program to perform the following questions and checkthe content of the memory variable inserted a display resultcommand ( )Cree un programa para ejecutar las cuestiones siguientes yverificar el contenido de la variable de memoria insertando uncomando de presentación del resultado ( )Crie um programa para executar as questões seguintes e paraverificar o conteúdo da variável de memória inserida a umcomando de resultado de exibição ( )Erstellen Sie ein Programm zur Ausführung der folgendenFragestellungen und prüfen Sie den Inhalt der in einenBildschirmresultat-Befehl ( ) eingesetzten SpeichervariablenCréez un programme pour effectuer les questions suivantes etvérifiez le contenu de la variable de mémoire par l�insertion de la commande d�affichage de résultat ( )Generare un programma per effettuare le seguenti domande econtrollare il contenuto della variabile di memoria inserito uncomando di risultato su display ( )Creëer een programma om de volgende vragen uit te voeren encontroleer of de inhoud van de geheugenvariabele eenresultaatopdracht ( ) invoegde.Opret et program, der udfører de følgende spørgsmål, ogundersøg indholdet i hukommelsesvariablen med en kommandotil visning af resultatet ( )
( )Napisz program do przeprowadzenia nast puj cych oblicze isprawd zawarto pami ci zmiennych ( ) uæywaj c poleceniawy wietlania wyniku ( )
( )
Membuat sebuah program untuk menjalankan perhitungansoal-soal dan mengecek isi dari variabel memori yang telahdisisipkan pada perintah hasil yang ditampilkan ( )
( )B = log ( A + 90 ), C = 13 x A, D = 51 ( A x B )
Ex � 68
Program Type : MAIN
Line Program
1 I N P U T A ;
2 B = l o g ( A + 9 0 )
3 C = 1 3 A ;
4 D = 5 1 / ( A B )
5 P R I N T " D = " , D ;
6 E N D
RUN
A = 10 C = 130 , D = 2.55
[ ]A =
PROGDD
10A = 1 0
PROGDD
[ ]C = 1 3 A ;
PROGP R O G
DD
[ 2nd ] [ VRCL ] [ ] [ ]A B C D E F
130.G H I
J K LPROGDD
[ CL/ESC ] [ ]D = 2 . 5 5
PROGDD